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		<title><![CDATA[Multiwfn forum / Energy from gaussian output files]]></title>
		<link>http://sobereva.com/wfnbbs/viewtopic.php?id=800</link>
		<description><![CDATA[The most recent posts in Energy from gaussian output files.]]></description>
		<lastBuildDate>Wed, 15 Mar 2023 16:23:26 +0000</lastBuildDate>
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			<title><![CDATA[Re: Energy from gaussian output files]]></title>
			<link>http://sobereva.com/wfnbbs/viewtopic.php?pid=3052#p3052</link>
			<description><![CDATA[<p>Dear Alessio Macorano,</p><p>What you calculated is electronic energy, rather than energy of complete dissociation reaction of the molecule.</p><p>The concept in quantum chemistry field closest to the so-called &quot;energy of complete dissociation reaction of a molecule&quot; is <em>atomization energy</em>. For example, for H2O molecule you should calculate 2*E(H) + E(O) - E(H2O).</p><p>Best,</p><p>Tian</p>]]></description>
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			<pubDate>Wed, 15 Mar 2023 16:23:26 +0000</pubDate>
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			<title><![CDATA[Energy from gaussian output files]]></title>
			<link>http://sobereva.com/wfnbbs/viewtopic.php?pid=3051#p3051</link>
			<description><![CDATA[<p>Dear Prof Tian Lu,</p><p>I have a question about the energy value obtained from the Gaussian output file.</p><p>I&#039;ve done opt + freq calculation on dichloromethane at B3LYP 6-31+G* as an example and I get an E(B3LYP)=-959.700528 HARTREE/PARTICLE, I know that this energy is related to complete dissociation reaction of the molecule.&#160; </p><p>If i use a 1 Hartree = 627.5 kcal/mol i get a huge number to be an energy value, is this correct? </p><p>Or is there another way to obtain an energy value in kcal/mol more reliable by common sense?</p><p>Thanks a lot !</p><p>Alessio Macorano</p>]]></description>
			<author><![CDATA[dummy@example.com (AlessioM)]]></author>
			<pubDate>Wed, 15 Mar 2023 13:55:29 +0000</pubDate>
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